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Sep 24, 2022 at 15:52 comment added Andrej Bauer I object to the first two sentences :-)
Sep 24, 2022 at 1:30 vote accept Jason Rute
Sep 23, 2022 at 7:55 answer added Christopher Hughes timeline score: 5
Sep 12, 2022 at 14:44 comment added Trebor It is not true that there is a function (V : VecSpace) -> BasisOf V in UA (i.e. from such a function we can deduce false). But with the HoTT axiom of choice it is provable that every vector space merely has a basis.
Sep 12, 2022 at 14:21 comment added Jason Rute @Trebor, Also, I don't understand what you are saying about LEM. Do you mean the type theoretic LEM A + (A -> empty) or propositional LEM p \/ not p? The latter would not be near strong enough. I still need something strong enough to prove that every vector space has a basis for example. (Unless propositional LEM and UC is a lot stronger than I realized.)
Sep 12, 2022 at 14:15 comment added Jason Rute @Trebor Or maybe I even need the Pi binder over types inside the propositional truncation: nonempty (Π (α : Sort*), nonempty α → α). This would just then be the propositional truncation of global choice. Is this what you meant? Would this be compatible with UA? (Again, if sort were replaced with set.)
Sep 12, 2022 at 13:57 comment added Trebor Yes, that one is equivalent to LEM (but "merely $A$" is crucially not living in Prop, because it only concerns propositional equalities, and must not mingle with definitional ones).
Sep 12, 2022 at 11:53 comment added Jason Rute @Trebor Or do by "propositional global choice" do you just mean nonempty (nonempty α → α). That would indeed be an interesting axiom. If so, do you have a citation that this is compatible with UA?
Sep 12, 2022 at 11:41 comment added Jason Rute @Trebor, I don't get how what you said is not a tautology. In base Lean, nonempty α ↔ (∃ x : α, true) and inhabited α → nonempty α. (Note nonempty is a Prop). Do you mean, (α : Sort*) (β : α -> Sort*) : (∀ x : α, nonempty (β x)) -> nonempty (Π (x : α), β x) which is basically formula 3.8.3 in the HoTT book (ignoring set vs type)? Yes, that might be a cleaner way to state the axiom of choice.
Sep 12, 2022 at 3:19 comment added Trebor Propositional global choice (i.e. if $A$ is not empty, then $A$ merely has an element) isn't incompatible with UA. And personally I think this is the "right one" to compare with the set theoretic GC, in the context of univalent foundations.
Sep 11, 2022 at 22:34 history edited Jason Rute CC BY-SA 4.0
Put all examples in Lean
Sep 11, 2022 at 22:29 history edited Jason Rute CC BY-SA 4.0
Fixed unique choice.
Sep 11, 2022 at 19:55 history asked Jason Rute CC BY-SA 4.0